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Simplify stream availability handling

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Just have a simply number of bytes argument to avoid a lot of
complexity.
This commit is contained in:
Pierre Ossman
2020-05-19 21:07:05 +02:00
committed by Lauri Kasanen
parent 92c7695981
commit 57a3c3bba8
20 changed files with 67 additions and 132 deletions
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17
common/rdr/BufferedOutStream.cxx
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@@ -71,22 +71,22 @@ void BufferedOutStream::flush()
ptr = sentUpTo = start;
}
size_t BufferedOutStream::overrun(size_t itemSize, size_t nItems)
void BufferedOutStream::overrun(size_t needed)
{
if (itemSize > bufSize)
if (needed > bufSize)
throw Exception("BufferedOutStream overrun: "
"requested size of %lu bytes exceeds maximum of %lu bytes",
(long unsigned)itemSize, (long unsigned)bufSize);
(long unsigned)needed, (long unsigned)bufSize);
// First try to get rid of the data we have
flush();
// Still not enough space?
while (itemSize > avail()) {
while (needed > avail()) {
// Can we shuffle things around?
// (don't do this if it gains us less than 25%)
if (((size_t)(sentUpTo - start) > bufSize / 4) &&
(itemSize < bufSize - (ptr - sentUpTo))) {
(needed < bufSize - (ptr - sentUpTo))) {
memmove(start, sentUpTo, ptr - sentUpTo);
ptr = start + (ptr - sentUpTo);
sentUpTo = start;
@@ -105,11 +105,4 @@ size_t BufferedOutStream::overrun(size_t itemSize, size_t nItems)
ptr = sentUpTo = start;
}
}
size_t nAvail;
nAvail = avail() / itemSize;
if (nAvail < nItems)
return nAvail;
return nItems;
}